Hi,
Yes, the len(output_items[0]), is either 1 or 2...
If I set_output_multiple to 10, then this value raises to 10.
It is dominated by the fact that one of the inputs to my block is much lower
than the other?? Input[0] is the data stream and has say 768 items, input[1] is
the packet average SNR, so it only has 1 or 2 items in the same period.
Forecast is currently
For I in range (len(ninput_items_required)):
Ninput_items_required[i] = noutput_items
Does this need to be altered for my case where I have two inputs with very
different requirements.
If I ever get my head around the scheduler in GNU radio, it will be a happy day
:)
D
-----Original Message-----
From: discuss-gnuradio-bounces+david.halls=toshiba-trel....@gnu.org
[mailto:discuss-gnuradio-bounces+david.halls=toshiba-trel....@gnu.org] On
Behalf Of Martin Braun
Sent: 11 March 2014 15:27
To: discuss-gnuradio@gnu.org
Subject: Re: [Discuss-gnuradio] output operand requires a reduction, but
reduction is not enabled
On 03/11/2014 04:24 PM, David Halls wrote:
> Please see the papers we've submitted so far this year. Not exactly
> WNC, yet... We're putting one together as we speak though.
>
> I am not sure I understand your reply fully...
>
> Len(out_bA1) is only 1 or 2, so I can only set one or two elements?
Is this before or after you assign something? What's len(output_items[0])?
> How can I extend the length of out_bA1, so I can output all of est_bA1m?
You can't, not in the work function. You can do things like
set_output_multiple() to influence the size of the output buffer.
> Or alternatively Is it possible for me to set
>
> "output_items[0][0:len(est_bA1m)] = est_bA1m"
That would work, if len(est_bA1m) < len(output_items[0]) AND they have the
right "shape" (in matrix terms).
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