On 12/18/06, Abel Tamayo <[EMAIL PROTECTED]> wrote: > $(".oneClass").each(moveCodeToImg(this))
To just expound on what Mike mentioned ... by saying, 'moveCodeToImg(this)' you are trying to call a function where it shouldn't be called. You could write it like this: $('.oneClass').each(function() { moveCodeToImg(this); }); -- Brandon Aaron _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/