On 12/18/06, Brandon Aaron <[EMAIL PROTECTED]> wrote:
To just expound on what Mike mentioned ... by saying,
'moveCodeToImg(this)' you are trying to call a function where it
shouldn't be called. You could write it like this:
$('.oneClass').each(function() { moveCodeToImg(this); });
pffft...should of noticed that myself. Thanks for clearing that up.
--
Aaron Heimlich
Web Developer
[EMAIL PROTECTED]
http://aheimlich.freepgs.com
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