So this means the function: $(function() {
var jqForm = $('#your-form-id'); jqForm.hide(); $('a').click(function() { jqForm.show(); }); }); will be called when the document / page is ready. And then I also need to have a different function in there for the radio selector -- where would it go -- in the main $(function) ? Sorry abt the newbie questions. thanks, pranav. Klaus Hartl wrote: > > unohoo schrieb: >> Hi, >> >> I'm a convert from prototype and so apologies if this may come out as a >> dummy question. >> >> What I intend to do is following: >> >> I have a link ( element). On click, it displays a form which has 2 radio >> elements. By default, this form is not visible. only when the element >> is >> clicked, the form becomes visible. Then, on form visible, user can select >> any radio button and then form is processed. >> >> >> In prototype, I used the hide, visible ,block elements for accomplishing >> the above. By default, the form had a :hide associated to it. >> >> How do I accomplish the same in Jquery ? > > > $(function() { > > var jqForm = $('#your-form-id'); > jqForm.hide(); > $('a').click(function() { > jqForm.show(); > }); > > }); > > > -- Klaus > > > _______________________________________________ > jQuery mailing list > discuss@jquery.com > http://jquery.com/discuss/ > > -- View this message in context: http://www.nabble.com/%3Ca%3E-on-click-show-form-tf2953602.html#a8261595 Sent from the JQuery mailing list archive at Nabble.com. _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/