Actually I did end up using hover(), it works better for what I'm trying to do...so hand over the dunce cap!
But now I also know how to bind the same function to multiple events if I ever want to do that... -- Josh ----- Original Message ----- From: David Dexter To: 'jQuery Discussion' Sent: Tuesday, March 27, 2007 3:21 PM Subject: Re: [jQuery] bind two events to same function I have my dunce cap. which corner do I go sit in? David Dexter | brilliantlemming.com | Brentwood, CA | 310.414.0949 ------------------------------------------------------------------------------ From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Aaron Heimlich Sent: Tuesday, March 27, 2007 3:02 PM To: jQuery Discussion Subject: Re: [jQuery] bind two events to same function On 3/27/07, David Dexter <[EMAIL PROTECTED]> wrote: Have a look at the hover() function it does exactly what you are looking for. Actually, it doesn't. hover() expects two different functions. From the API docs: "Whenever the mouse cursor is moved over a matched element, the first specified function is fired. Whenever the mouse moves off of the element, the second specified function fires." Source: http://docs.jquery.com/Events#hover.28_over.2C_out_.29 What Josh wants to do is bind the *exact same function* to do different events (which is what I showed him how to do). -- Aaron Heimlich Web Developer [EMAIL PROTECTED] http://aheimlich.freepgs.com ------------------------------------------------------------------------------ _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/
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