Hi everybody, I have 3 models:
built-in User model, class Project(models.Model): author = models.ForeignKey(User, verbos_name=_('Author'), related_name='projects') title = models.charField(_('Title'), max_length=150) class Vote(models.Model): project = models.ForeignKey(Project, verbos_name=_('Project'), related_name='votes') user = models.ForeignKey(User, verbos_name=_('User'), related_name='votes') date = models.DateTimeField(_('Date'), default=datetime.datetime.now) So users can be authors of the projects and they can vote for the projects. I have the view to show list of projects, when I want to order projects by votes.count As far as Project model does not contain the Votes field (it is realised as Many-To-Many table), I do not know how to write DB query like this: projects = Project.objects.order_by('votes') So I decided to take the projects as follows: projects = Project.object.all() And then foreach project count the votes number. But is is time- consuming. Also I do not know if this is true: for project in projects project.votes = project.votes.count projects = sorted(projects, votes) Do you know any approach to do it on the fly? I mean the most efective way. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.