You can subclass the User admin and then unregister the default admin
and register your new subclassy admin (subclassy is a word)
in admin.py:
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User
class MyNewUserAdmin(UserAdmin):
list_filter = UserAdmin.list_filter + ('groups',)
admin.site.unregister(User)
admin.site.register(User, MyNewUserAdmin)
On Aug 11, 9:42 am, Wim Feijen <wimfei...@gmail.com> wrote:
> Hello,
>
> I am banging my brain against the wall but it doesn't help and all I
> get is brain damage. Maybe you can help me find a solution for the
> following problem?
>
> How can I add a filter to the django admin User interface (/admin/auth/
> user/) so I can filter Users by Group?
>
> What I have thought of, is:
> 1. Alter the template templates/admin/auth/user/change_list.html and
> edit it to add a list of existing groups as links.
> 2. Redirect to ?group_id=1. THIS STEP FAILS!
> 3. Write a custom UserAdmin and overwrite the queryset method to show
> only users of a group, thus:
>
> class UserAdmin(admin.ModelAdmin):
> model = User
>
> def queryset(self, request):
> group_id = request.GET.get('group_id', '')
> if group_id:
> return Group.objects.get(id=group_id).user_set.all()
> else:
> return super(UserAdmin, self).queryset(request)
>
> try:
> admin.site.unregister(User)
> except admin.sites.Unregistered:
> pass
> admin.site.register(User, UserAdmin)
>
> The missing link is step 2. How on earth do I get a request.GET
> parameter through django's normal filtering process/ how can I combine
> it. When I try '/admin/auth/user/?group_id=1', django redirects me to
> '/admin/auth/user/?e=1'
>
> Any help and tips will be very much appreciated, thank you!
>
> If someone's has ever done this, I'd really like to know!
>
> Wim
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