So simple and so great!
Thanks!
On 11 aug, 21:50, Nick <nickt...@gmail.com> wrote:
> You can subclass the User admin and then unregister the default admin
> and register your new subclassy admin (subclassy is a word)
>
> in admin.py:
>
> from django.contrib.auth.admin import UserAdmin
> from django.contrib.auth.models import User
>
> class MyNewUserAdmin(UserAdmin):
> list_filter = UserAdmin.list_filter + ('groups',)
>
> admin.site.unregister(User)
> admin.site.register(User, MyNewUserAdmin)
>
> On Aug 11, 9:42 am, WimFeijen<wimfei...@gmail.com> wrote:
>
>
>
> > Hello,
>
> > I am banging my brain against the wall but it doesn't help and all I
> > get is brain damage. Maybe you can help me find a solution for the
> > following problem?
>
> > How can I add a filter to the django admin User interface (/admin/auth/
> > user/) so I can filter Users by Group?
>
> > What I have thought of, is:
> > 1. Alter the template templates/admin/auth/user/change_list.html and
> > edit it to add a list of existing groups as links.
> > 2. Redirect to ?group_id=1. THIS STEP FAILS!
> > 3. Write a custom UserAdmin and overwrite the queryset method to show
> > only users of a group, thus:
>
> > class UserAdmin(admin.ModelAdmin):
> > model = User
>
> > def queryset(self, request):
> > group_id = request.GET.get('group_id', '')
> > if group_id:
> > return Group.objects.get(id=group_id).user_set.all()
> > else:
> > return super(UserAdmin, self).queryset(request)
>
> > try:
> > admin.site.unregister(User)
> > except admin.sites.Unregistered:
> > pass
> > admin.site.register(User, UserAdmin)
>
> > The missing link is step 2. How on earth do I get a request.GET
> > parameter through django's normal filtering process/ how can I combine
> > it. When I try '/admin/auth/user/?group_id=1', django redirects me to
> > '/admin/auth/user/?e=1'
>
> > Any help and tips will be very much appreciated, thank you!
>
> > If someone's has ever done this, I'd really like to know!
>
> > Wim
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