In your view code, include { 'categories':BookCategory.objects.all
() } in your context.
Then, in the template
<ul>
{% for cat in categories %}
<li>{{ cat }}
<ul>
{% for book in cat.book_set.all %}
<li>{{ book }}</li>
{% endfor %}
</ul>
</li>
{% endfor %}
</ul>
This assumes you have the __str__() method of Book and BookCategory
set to output something you're happy with. If you'd prefer, you can
use {{ cat.name }} and {{ book.name }} (or a similar idea, depending
on what the actual field is called in your model) instead.
Todd
On Aug 5, 2006, at 11:13 AM, [EMAIL PROTECTED] wrote:
>
> Hi,
>
> Using the models below, I want a single page to show:
>
> bookcategory1
> book1
> book2
> bookcategory2
> book1
> book2
> ...
> bookcategory3
> ...
> ...
> ...
>
> ##################################
>
> # Models
>
> class BookCategory(models.Model):
> ...
>
> class Book(models.Model):
> ...
> category = models.ForeignKey(BookCategory)
> ...
>
> ##################################
>
> What would be the preferred way to do this?
> Can it be done without templatetags? How?
>
> If the solution must rely on templatetags, can you give me a short
> example of how this templatetag might look?
>
> Thanks very much!
>
> Best regards,
> Cello
>
>
> >
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