hello, I am trying to migrate my function based views to class based ones. I have a search page with a form (which is represented by MySearchForm class). The form's action URL is set to the current page (<form action="." method="post">). When the form is submitted the search results are shown in the page below the form. in other words I do not have a "success URL" used by several ready-made views in django.views.generic namespace, so I think I cannot use them. Does this mean I need to write my view from scratch? so far I think that I need to have:
class MySearchView(ListView, ProcessFormView) : ... Does this look right? If so, where does MySearchForm come in to play? how do I instantiate it and check for validity? I am new to this, so I am lost because the documentation is very raw. Basically my question is how do I implement such a view? would someone please help? thanks konstantin -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
