Thanks every one, I've manage to work this around. The solution might not be the best, but it's working: In the view I call the *do_something_slow()* in a new thread, and in the end of it(after the role process is done) it change the model of a class to add the feedback. While the thread is running it renders the template to the user(with a * "Loading..."* message). Then I've made a *ajax_get_feed_back() *view to get this feedback.
In the template, I made a simple JS that every second tries to get the feedback via ajax. And if it gets the feedback it stops requesting it. =) But I still wanted to know how to use the celery in this case =/ But got very lost in that, does any one have a example(code) of something similar to do with it? In the docs I only found examples of process that are kind of tasks... to run every hour, or things like that. Em segunda-feira, 19 de março de 2012 15h18min09s UTC-3, Arruda escreveu: > > *(I've created a topic like this a few minutes ago, but was using the old > google groups, and now it's broken. So I created a new one using the new > google groups).* > Hi, I'll try to explain the best I can my problem, and I don't know if > what I'm trying to archive is the best way to get where I want, but > here is it: > I want that a specific view to run in a new thread, ex: > * def foo(request): > do_something_slow() > return httpResponse* > > But I DON'T want that a new thread is run inside the view, the view it > self should be runned in another thread, ex: > * > def foo(request): > t = thread(target=do_something_slow()....) > t.daemon = True > t.start() > > return httpResponse > * > This way when a user A access any page the site will load, even if a > user B is accessing the 'foo' view. > But the B user when access the view 'foo' will load it just a if if > was a normal view( will be slow and will render the response just > after do_something_slow() finished running). > > I don't know if this is what I want, but I believe that there is > another way around: > when user B calls foo view, it will render to him a page with a JS(I > don't know JS either, so correct me if I'm talking nonsense) that say > its "Loading..." > And after the do_someting_slow() finished running if will change the > content of the page to whatever the result of "do_something_slow" was. > > Thanks for the attention. > -- You received this message because you are subscribed to the Google Groups "Django users" group. To view this discussion on the web visit https://groups.google.com/d/msg/django-users/-/ST6KqE0uPqsJ. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
