hey xactive...
a simple solution, without bells & whistles could be this (assuming
File.file_obj is defined as a Django FileField):
On 09/17/2012 01:15 PM, xactive wrote:
I have little experience with Django/Python but have a problem that I
need to solve.
Currently I have a button action that allows users of a website to
download files from a displayed list. I want to add a button to allow
users to delete the files if required.
The current download button is set up as follows on the page itself:
<a id="download" href="/portal/files/{{ file.id
}}/?action=download">Download</a>
add to your template:
<a id="delete" href="/portal/files/{{ file.id }}/?action=delete">Delete</a>
And as far as I can see there is a file called views.py which contains
code as follows:
@login_required(login_url='/portal/login/', redirect_field_name=None)
def file_view(request, id, template_name='portal/file_view.html'):
try:
f = File.objects.get(pk=id)
except File.DoesNotExist:
raise Http404
if request.user not in f.recipients.all() and request.user != f.owner:
return HttpResponseForbidden()
if request.GET.has_key('action'):
action = request.GET['action']
if action == 'download':
filename = f.file_obj.name.rsplit('/', 1)[1]
response = HttpResponse()
response['Content-Disposition'] = 'attachment; filename=%s' % filename
response['Content-Length'] = ''
response['X-Accel-Redirect'] = '/%s' % f.file_obj.name
return response
elif action == 'delete':
f.file_obj.delete()
# read https://docs.djangoproject.com/en/dev/ref/models/fields/
return render_to_response('portal/file_deleted.html', {},
context_instance=RequestContext(request))
return render_to_response(template_name, {
'file': f
}, context_instance=RequestContext(request))
you still have to create the template file 'portal/file_deleted.html'.
or you do a redirect to another URL instead...
Can somebody please help me to create an action to delete files?
hth,
Sebastian
--
Sebastian Henschel, Python Developer Web
txtr GmbH | Rosenthaler Str. 13 | 10119 Berlin | Germany
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