You need to capture the id parameter in your URL by wrapping it in parentheses: 
([0-9])

Sent from my iPhone

On Nov 12, 2012, at 12:49 AM, muhammed riyas <muhammedriyas.2...@gmail.com> 
wrote:

> Request Method:GET
> Request URL:http://localhost:9744/employee/1/
> Exception Type:TypeError
> Exception Value:individual() takes exactly 2 arguments (1 given)
> Exception 
> Location:/home/user/google_appengine/lib/django_0_96/django/core/handlers/base.py
>  in get_response, line 77
> 
> 
> 
> url is  (r'^employee/[0-9]+/$','qburstemployeeapp.main.views.individual'),
> 
> in this the [0-9]+ denotes id number for the user ...
> 
> in my view...
> 
> 
> 
> def individual(request,id):
>     employees = Employeeprofile.all()
>     for employee in employees:
>         if(employee.key().id() == id):
>               return render_to_response('main/individual1.html', { 'employee' 
> : employee }) 
> 
> What is the mistake?...
> 
> 
> Thanks in advance....
> 
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