You have to convert id to int
W dniu 12.11.2012 09:37, muhammed riyas pisze:
thanks it works fine, but the if statement is not working,,, why? it
always gives the first result?.....
On Mon, Nov 12, 2012 at 1:28 PM, Jonathan D. Baker
<jonathandavidba...@gmail.com <mailto:jonathandavidba...@gmail.com>>
wrote:
You need to capture the id parameter in your URL by wrapping it in
parentheses: ([0-9])
Sent from my iPhone
On Nov 12, 2012, at 12:49 AM, muhammed riyas
<muhammedriyas.2...@gmail.com
<mailto:muhammedriyas.2...@gmail.com>> wrote:
Request Method:GET
Request URL:http://localhost:9744/employee/1/
Exception Type:TypeError
Exception Value:individual() takes exactly 2 arguments (1 given)
Exception
Location:/home/user/google_appengine/lib/django_0_96/django/core/handlers/base.py
in get_response, line 77
url
is (r'^employee/[0-9]+/$','qburstemployeeapp.main.views.individual'),
in this the [0-9]+ denotes id number for the user ...
in my view...
def individual(request,id):
employees = Employeeprofile.all()
for employee in employees:
if(employee.key().id() == id):
return render_to_response('main/individual1.html', { 'employee' :
employee })
What is the mistake?...
Thanks in advance....
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Pozdrawiam,
Dominik Przybysz
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