Opps, sorry. I was actually trying to ask how one would get a hold of the
current model in this admin form, but the Esc key for some reason sent the
message.
The above function works, but the instance is not a model instance which
can be saved. How would I go about getting the current RssFeedPage model
which pertains to the form instance?

This works great on the cli --> from Django_project.update_rss_feeds import
*; m = get_models(); rss_page = m[1]; rss_item=m[2];
UpdateFeeds().parse_feed(page_model_instance=rss_page.objects.get(pk=1),
rss_item=rss_item, feed_url="
http://rss.nytimes.com/services/xml/rss/nyt/HomePage.xml";)

..because I pass in a usable model to ->
parse_feed(page_model_instance=model)

Note: this script will be open-sourced shortly. I will post the repo when
it is ready :)


On Sat, Jan 25, 2014 at 2:29 PM, Robert Steckroth <robertsteckr...@gmail.com
> wrote:

>
>
> class RssFeedPageForm(forms.ModelForm):
>     class Meta:
>         model = RssFeedPage
>
>     def clean_link(self):
>         self.instance.save()
>         page_model_instance=self.instance, rss_item=RssFeedItem,
> feed_url=self.data['link'])
>    UpdateFeeds().parse_feed(page_model_instance=self.instance,
> rss_item=RssFeedItem, feed_url=self.data['link'])
>
>
>
> --
> <surgemcgee>
>
>
>
>


-- 
<surgemcgee>

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