So that does not work. Is there a builtin method that will allow me to call
the script before the form is rendered in save_model?
form = RssFeedPageForm # <-- how can this be loaded with UpdateFeeds
ValidationErrors?
def save_model(self, request, obj, form, change):
# UpdateFeeds().parse_feed will raise VailidationError
UpdateFeeds().parse_feed(update_feed_data=True,
update_item_data=True, page_model_instance=obj, rss_item=RssFeedItem,
feed_url=form.data['link'])
On Sat, Jan 25, 2014 at 2:37 PM, Robert Steckroth <robertsteckr...@gmail.com
> wrote:
> Opps, sorry. I was actually trying to ask how one would get a hold of the
> current model in this admin form, but the Esc key for some reason sent the
> message.
> The above function works, but the instance is not a model instance which
> can be saved. How would I go about getting the current RssFeedPage model
> which pertains to the form instance?
>
> This works great on the cli --> from Django_project.update_rss_feeds
> import *; m = get_models(); rss_page = m[1]; rss_item=m[2];
> UpdateFeeds().parse_feed(page_model_instance=rss_page.objects.get(pk=1),
> rss_item=rss_item, feed_url="
> http://rss.nytimes.com/services/xml/rss/nyt/HomePage.xml";)
>
> ..because I pass in a usable model to ->
> parse_feed(page_model_instance=model)
>
> Note: this script will be open-sourced shortly. I will post the repo when
> it is ready :)
>
>
> On Sat, Jan 25, 2014 at 2:29 PM, Robert Steckroth <
> robertsteckr...@gmail.com> wrote:
>
>>
>>
>> class RssFeedPageForm(forms.ModelForm):
>> class Meta:
>> model = RssFeedPage
>>
>> def clean_link(self):
>> self.instance.save()
>> page_model_instance=self.instance, rss_item=RssFeedItem,
>> feed_url=self.data['link'])
>> UpdateFeeds().parse_feed(page_model_instance=self.instance,
>> rss_item=RssFeedItem, feed_url=self.data['link'])
>>
>>
>>
>> --
>> <surgemcgee>
>>
>>
>>
>>
>
>
> --
> <surgemcgee>
>
>
>
>
--
<surgemcgee>
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