Hi,
This might help you get going (see at the end). I modified a bit the
function that sends the mail in Django. It is probably very far from
as good as it could be.
I am actually surprised as well that there's no function for that.
Hope it helps,
G
# Use this module for e-mailing.
from django.conf import settings
from django.utils.html import strip_tags, strip_spaces_between_tags
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
from email.Header import Header
import smtplib, rfc822
class BadHeaderError(ValueError):
pass
class SafeMIMEMultipart(MIMEMultipart):
def __setitem__(self, name, val):
"Forbids multi-line headers, to prevent header injection."
if '\n' in val or '\r' in val:
raise BadHeaderError, "Header values can't contain
newlines (got %r for header %r)" % (val, name)
if name == "Subject":
val = Header(val, settings.DEFAULT_CHARSET)
MIMEText.__setitem__(self, name, val)
def send_mass_mail(datatuple, fail_silently=False,
auth_user=settings.EMAIL_HOST_USER,
auth_password=settings.EMAIL_HOST_PASSWORD):
"""
Given a datatuple of (subject, message, from_email, recipient_list), sends
each message to each recipient list. Returns the number of e-mails sent.
If from_email is None, the DEFAULT_FROM_EMAIL setting is used.
If auth_user and auth_password are set, they're used to log in.
"""
# We prepare the server to send messages.
try:
server = smtplib.SMTP(settings.EMAIL_HOST, settings.EMAIL_PORT)
if auth_user and auth_password:
server.login(auth_user, auth_password)
except:
#print 'Server preparation did not work'
if fail_silently:
return
raise
num_sent = 0
# We prepare the message to be sent.
for subject, message, from_email, recipient_list in datatuple:
if not recipient_list:
continue
from_email = from_email or settings.DEFAULT_FROM_EMAIL
# Create the root message and fill in the basic headers
msgRoot = MIMEMultipart('related')
msgRoot['Subject'] = subject
msgRoot['From'] = from_email
msgRoot['To'] = ', '.join(recipient_list)
msgRoot['Date'] = rfc822.formatdate()
msgRoot.preamble = 'This is a multi-part message in MIME format.'
# Encapsulate the plain and HTML versions of the message body in an
# 'alternative' part, so message agents can decide which they
want to display.
msgAlternative = MIMEMultipart('alternative')
msgRoot.attach(msgAlternative)
# This is the html message.
msgText = MIMEText(message, 'html', settings.DEFAULT_CHARSET)
msgAlternative.attach(msgText)
# This is the alternative plain text message.
msgText =
MIMEText(strip_spaces_between_tags(strip_tags(message)), 'plain',
settings.DEFAULT_CHARSET)
msgAlternative.attach(msgText)
# We send the actual message
try:
server.sendmail(from_email, recipient_list, msgRoot.as_string())
num_sent += 1
except:
if not fail_silently:
raise
# We quit elegantly
try:
server.quit()
except:
if fail_silently:
return
raise
return num_sent
On 10/14/06, Don Arbow <[EMAIL PROTECTED]> wrote:
>
> On Oct 13, 2006, at 2:58 PM, sdm wrote:
> >
> > Hi, I look in the documentation, but don't have found how can I
> > send an
> > email with html content, how can I do it?
>
>
>
> That's because it's not a Django question, but a Python one. Here's a
> link to a page showing how to send HTML emails using the Python
> libraries:
>
> http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/473810
>
> Don
>
>
> >
>
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