On 01/11/06, Gábor Farkas <[EMAIL PROTECTED]> wrote:
>
> samuel wrote:
> >>> I'm probably just not seeing it, but how do  I go about getting the
> >>> index of an item in a query set? I.E., this article is the Xth article
> >>> in this queryset of articles sorted by date.
> >> If you're looping through them in the template with the 'for' tag,
> >> each time through the loop you'll have access to a variable called
> >> 'forloop.counter' which has this information; the first time through
> >> it will be 1, the second time it will be 2, and so on.
> >>
> >> See http://www.djangoproject.com/documentation/templates/#for for details.
> >>
> >
> > Thanks but I guess I'm looking for something a bit different. Here's
> > exactly what I'm trying to do: I have  articles that are chunked into
> > groups of 10 arbitrarily based on their date. So when a new article is
> > added the groups change. When you go to an article page, I want to
> > display the chunk that the article belongs to. So if the article is
> > 19th, display a list of articles 11-20.
> >
> > If I'm thinking through this correctly, I need to know the articles
> > location in the queryset before I get to the template and then slice
> > the queryset as necessary. How would I go about this? Just iterate
> > through and backtrack when I get there?
> >
>
> if the number of articles is not too high, then simply generate their
> number in the view... like:
>
> queryset = Article.objects.all()
>
> items = list(enumerate(queryset))
>
> which is basically the same as:
>
> items = zip (range(queryset.count()), queryset)
>
> or, if you want it 1-based and not 0-based:
>
> items = zip (range(1,queryset.count()+1), queryset)
>
> the problem with these is that it fetches all the article-objects.

Since the only way to do this is programmatically in python it might
be better to use raw sql for this instead.

>
> gabor
>
> >
>


-- 
http://grimboy.co.uk

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