Frankie Robertson wrote:
> On 01/11/06, Gábor Farkas <[EMAIL PROTECTED]> wrote:
>> samuel wrote:
>>>>> I'm probably just not seeing it, but how do  I go about getting the
>>>>> index of an item in a query set? I.E., this article is the Xth article
>>>>> in this queryset of articles sorted by date.
>>>> If you're looping through them in the template with the 'for' tag,
>>>> each time through the loop you'll have access to a variable called
>>>> 'forloop.counter' which has this information; the first time through
>>>> it will be 1, the second time it will be 2, and so on.
>>>>
>>>> See http://www.djangoproject.com/documentation/templates/#for for details.
>>>>
>>> Thanks but I guess I'm looking for something a bit different. Here's
>>> exactly what I'm trying to do: I have  articles that are chunked into
>>> groups of 10 arbitrarily based on their date. So when a new article is
>>> added the groups change. When you go to an article page, I want to
>>> display the chunk that the article belongs to. So if the article is
>>> 19th, display a list of articles 11-20.
>>>
>>> If I'm thinking through this correctly, I need to know the articles
>>> location in the queryset before I get to the template and then slice
>>> the queryset as necessary. How would I go about this? Just iterate
>>> through and backtrack when I get there?
>>>
>> if the number of articles is not too high, then simply generate their
>> number in the view... like:
>>
>> queryset = Article.objects.all()
>>
>> items = list(enumerate(queryset))
>>
>> which is basically the same as:
>>
>> items = zip (range(queryset.count()), queryset)
>>
>> or, if you want it 1-based and not 0-based:
>>
>> items = zip (range(1,queryset.count()+1), queryset)
>>
>> the problem with these is that it fetches all the article-objects.
> 
> Since the only way to do this is programmatically in python it might
> be better to use raw sql for this instead.
> 

hmm.. how?

gabor

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