Hi all,
Thanks for all the feedback! I was expecting either a "do it like
this" or a "sorry, it can't be done" type response - this is much
better.
Tim - my initial solution was to use a differentiator view as you
suggested. I thought this was a little messy because it dragged URL
logic into my views, so I opened this thread to see if there was a
better option. Before Emanuele's last comment I was also limited to
not used generic views if I did it that way.
Emanuele - you're totally right that it's a matter of opinion; sadly
I'm working with an existing URL structure so I've got to do it this
way. At least now I know I've surveyed all the options.
Thanks again all,
Matt.
On Jul 30, 7:57 pm, Emanuele Pucciarelli <[EMAIL PROTECTED]> wrote:
> Il giorno 30/lug/07, alle ore 17:21,Mattha scritto:
>
> > For instance, if you also had categories of users and wanted to be
> > able to list the users in each category, a 'human-friendly' url
> > scheme might look like this:
>
> >www.mysite.com/users/matt--> go to my area
> >www.mysite.com/users/jess--> go to Jess' area
> >www.mysite.com/users/mark--> go to Mark's area
> >www.mysite.com/users/premium--> list all premium members
> >www.mysite.com/users/economy--> list all economy members
>
> Whether that's more or less human-friendly is surely a matter of
> opinion; for one, I wouldn't regard mixing users and user groups that
> way as friendly - I'd find it misleading at best - but it's just an
> opinion. Moreover, you should take care not to have objects of a
> different kind with the same name.
>
> If you still wanted to do so *and* keep using generic views, you
> could call them from a custom view. As an example, you could have in
> your URL configuration a line like this:
>
> from yourapp.views import sorter
>
> [...]
>
> ( r'^users/(?P<slug>\w+)/$', sorter, {'slug_field': 'name',}, ),
>
> and in your views.py file:
>
> from django.core.exceptions import ObjectDoesNotExist
> from django.http import Http404
> from django.views.generic.simple.list_detail import object_detail
> from yourapp.models import User, Category
>
> def sorter(request, **kwargs):
> for model in (Category, User, [...]):
> try:
> kwargs['queryset'] = model.objects.all()
> return object_detail(request, **kwargs)
> except ObjectDoesNotExist:
> pass
> return Http404
>
> and this would let you map any object to the same URL scheme. But
> first - is that really what you'd want?
>
> Regards,
>
> --
> Emanuele
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