You have two choices. Either you can add .exclude() using the __in to
avoid get the duplicates in the first place. Or you could iterate over
the 3 pubs and append them to a list with an if statement. Something
like this:
list = []
for pub in publications123:
If pub not in list:
list.append(pub)
On 25 Feb., 21:54, Jesse <adles...@gmail.com> wrote:
> > I believe this would work:
>
> > publications = Publication.objects.filter(techpubcombo__technology=t)
>
> > Regards,
>
> > --
> > Christian Joergensenhttp://www.technobabble.dk
>
> Hello Christian,
>
> Thank you so much for your answer. I have been struggling with the
> users group to get that syntax (I must not have been explaining it
> well enough). Now I need the syntax for the next step, which I'm
> hoping you can help with.
>
> I have three statements:
> publications = Publication.objects.filter(techpubcombo__technology=t)
> publications2 = Publication.objects.filter(pathpubcombo__pathology=p)
> publications3 = Publication.objects.filter(commpubcombo__commodity=c)
>
> I need to combine the three sets into one set to eliminate duplication
> in the publications and then output the final set to the template.
>
> Thanks for any help!
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