Hi users and devs
In the next example for pagination:
contact_list = Contacts.objects.all()
paginator = Paginator(contact_list, 25) # Show 25 contacts per
page
Consider that Contacts.objects.all() returns a list with 1.000.000
objects, and I want to paginate to 25 objects per page. Wouldn't be
significantly more fast to query for Contacts.objects.all()
[offset:limit]? Instead of cut a big list and querying for all objects
at the same time?
Regards,
Rodrigo
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