OH! It does it alone! Another awesome thing to my awesomeness list of django.
2009/5/20 Rodrigo <rali...@gmail.com> > Hi users and devs > > In the next example for pagination: > > contact_list = Contacts.objects.all() > paginator = Paginator(contact_list, 25) # Show 25 contacts per > page > > Consider that Contacts.objects.all() returns a list with 1.000.000 > objects, and I want to paginate to 25 objects per page. Wouldn't be > significantly more fast to query for Contacts.objects.all() > [offset:limit]? Instead of cut a big list and querying for all objects > at the same time? > > Regards, > Rodrigo -- Rodrigo Aliste P. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
