Hey guys thanks for your respond. First of all i read the tutorial
and the form works in /search with the template and the view. For now
I am trying to achieve a searchfield in another folder, /blog. Are you
guys saying i have to copy/ repeat the form in the /blog view and
template? To be as DRY as possible I'd like to have 1 template/view
search function and I'd like to pass data from elsewhere to that
place. So I understand my question was a bit vague but what I'd like
to do in the /blog template is:
<form method="get" action="../search/"> ********* send from
/blog to template/view of search
<table>
{{ form.as_table }} ********* load form from
/search template/view into /blog
<tr>
<td> </td>
<td>
<input type="submit" value="Search">
</td>
</tr>
</table>
This is the (standard) views.py from haystack which i have in the app
folder: http://dpaste.com/132922/
And this is the (standard) forms.py http://dpaste.com/132923/
Thanks
2009/12/13 oliver <oliver.bock...@gmail.com>:
> Sounds like you are not creating the form in your view .. read the
> tutorial the part about creating a form ..
> you need the form class, and the view that process your form (a)
> creates an empty form b) process the submitted one)
>
> see this relative simple example of a login form ..
>
> class userLoginForm(forms.Form):
> email = forms.CharField(max_length=45, label="Email address",
> error_messages={'required': 'Please enter an email address.'})
> password = forms.CharField(widget=forms.PasswordInput(),
> label="Password", error_messages={'required': 'Please enter a
> password.'})
>
>
> def userLogin(request):
> context_instance = RequestContext(request)
> try:
> nextUrl = request.GET['next']
> except:
> nextUrl = "/myopal/"
> if request.POST:
> form = userLoginForm(request.POST)
> username = request.POST['email']
> password = request.POST['password']
> if form.is_valid():
> user = authenticate(username=username, password=password)
> if user is not None:
> if user.is_active:
> login(request, user)
> return HttpResponseRedirect(nextUrl)
> else:
> error = "This account as been disabled, please contact
> support."
> return render_to_response('registration/login.html',
> {'form': form, 'login_error': error, 'nextUrl': nextUrl},
> context_instance)
> else:
> error = "Wrong details entered, please try again."
> return render_to_response('registration/login.html', {'form':
> form, 'login_error': error, 'nextUrl': nextUrl}, context_instance)
> else:
> return render_to_response('registration/login.html', {'form':
> form, 'nextUrl': nextUrl}, context_instance)
> else:
> form = userLoginForm()
> return render_to_response('registration/login.html', {'form': form,
> 'nextUrl': nextUrl}, context_instance)
>
>
>
> On Dec 12, 11:04 pm, GoSantoni <mj.schuur...@gmail.com> wrote:
>> Hey i've got a very basic question about django form processing. Got
>> haystack installed and searching works fine in the standard search
>> template (http://haystacksearch.org/docs/tutorial.html#search-
>> template) in the /search . Though i want to use the search box defined
>> by {{ form.as_table }} in another template in /blog . Just copying
>> {{ form.as_table }} fails to display the input field so what part of
>> the views.py or the forms.py needs to be copied from the haystack app?
>> Or what is another solution? So far in /blogs/blogs.html
>>
>> <form method="get" action="../search/">
>> <table>
>> {{ form.as_table }}
>>
>> <tr>
>> <td> </td>
>> <td>
>> <input type="submit" value="Search">
>> </td>
>> </tr>
>> </table>
>>
>> My goal is just to display the input box and send the query to /search
>> so the results are displayed on that page
>>
>> Thanks in advance!
>
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>
--
Mark Schuuring
M: mj.schuur...@gmail.com
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