Oh and I am not familiar with Ajax.... I am sorry because I've been
told that's a way to handle it...
Regards
2009/12/13 Mark Schuuring <mj.schuur...@gmail.com>:
> Hey guys thanks for your respond. First of all i read the tutorial
> and the form works in /search with the template and the view. For now
> I am trying to achieve a searchfield in another folder, /blog. Are you
> guys saying i have to copy/ repeat the form in the /blog view and
> template? To be as DRY as possible I'd like to have 1 template/view
> search function and I'd like to pass data from elsewhere to that
> place. So I understand my question was a bit vague but what I'd like
> to do in the /blog template is:
>
> <form method="get" action="../search/"> ********* send from
> /blog to template/view of search
> <table>
> {{ form.as_table }} ********* load form from
> /search template/view into /blog
> <tr>
> <td> </td>
> <td>
> <input type="submit" value="Search">
> </td>
> </tr>
> </table>
>
> This is the (standard) views.py from haystack which i have in the app
> folder: http://dpaste.com/132922/
> And this is the (standard) forms.py http://dpaste.com/132923/
>
> Thanks
>
> 2009/12/13 oliver <oliver.bock...@gmail.com>:
>> Sounds like you are not creating the form in your view .. read the
>> tutorial the part about creating a form ..
>> you need the form class, and the view that process your form (a)
>> creates an empty form b) process the submitted one)
>>
>> see this relative simple example of a login form ..
>>
>> class userLoginForm(forms.Form):
>> email = forms.CharField(max_length=45, label="Email address",
>> error_messages={'required': 'Please enter an email address.'})
>> password = forms.CharField(widget=forms.PasswordInput(),
>> label="Password", error_messages={'required': 'Please enter a
>> password.'})
>>
>>
>> def userLogin(request):
>> context_instance = RequestContext(request)
>> try:
>> nextUrl = request.GET['next']
>> except:
>> nextUrl = "/myopal/"
>> if request.POST:
>> form = userLoginForm(request.POST)
>> username = request.POST['email']
>> password = request.POST['password']
>> if form.is_valid():
>> user = authenticate(username=username, password=password)
>> if user is not None:
>> if user.is_active:
>> login(request, user)
>> return HttpResponseRedirect(nextUrl)
>> else:
>> error = "This account as been disabled, please contact
>> support."
>> return render_to_response('registration/login.html',
>> {'form': form, 'login_error': error, 'nextUrl': nextUrl},
>> context_instance)
>> else:
>> error = "Wrong details entered, please try again."
>> return render_to_response('registration/login.html', {'form':
>> form, 'login_error': error, 'nextUrl': nextUrl}, context_instance)
>> else:
>> return render_to_response('registration/login.html', {'form':
>> form, 'nextUrl': nextUrl}, context_instance)
>> else:
>> form = userLoginForm()
>> return render_to_response('registration/login.html', {'form': form,
>> 'nextUrl': nextUrl}, context_instance)
>>
>>
>>
>> On Dec 12, 11:04 pm, GoSantoni <mj.schuur...@gmail.com> wrote:
>>> Hey i've got a very basic question about django form processing. Got
>>> haystack installed and searching works fine in the standard search
>>> template (http://haystacksearch.org/docs/tutorial.html#search-
>>> template) in the /search . Though i want to use the search box defined
>>> by {{ form.as_table }} in another template in /blog . Just copying
>>> {{ form.as_table }} fails to display the input field so what part of
>>> the views.py or the forms.py needs to be copied from the haystack app?
>>> Or what is another solution? So far in /blogs/blogs.html
>>>
>>> <form method="get" action="../search/">
>>> <table>
>>> {{ form.as_table }}
>>>
>>> <tr>
>>> <td> </td>
>>> <td>
>>> <input type="submit" value="Search">
>>> </td>
>>> </tr>
>>> </table>
>>>
>>> My goal is just to display the input box and send the query to /search
>>> so the results are displayed on that page
>>>
>>> Thanks in advance!
>>
>> --
>>
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>>
>>
>
>
>
> --
> Mark Schuuring
> M: mj.schuur...@gmail.com
>
--
Mark Schuuring
M: mj.schuur...@gmail.com
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