On Jan 7, 4:23 pm, Andreas Pfrengle <a.pfren...@gmail.com> wrote: > On 7 Jan., 13:22, Tomasz Zieliñski <tomasz.zielin...@pyconsultant.eu> > > > > MyForm(forms.Form): > > > myfield = forms.ChoiceField(choices=CHOICES) > > > 1. Maybe you could use ModelChoiceField: > > >http://docs.djangoproject.com/en/dev/ref/forms/fields/#modelchoicefield > > > 2. You could populate choices on each request, by writing custom > > __init__ in MyForm: > > > def __init__(self, post=None, request=None): > > if post: > > super(MyForm, self).__init__(post) # bound form > > else: > > super(MyForm, self).__init__() # unbound form > > > self.fields['myfield'].choices = zip( > > [x.number for x in MyModel.objects.all()], > > [x.locale.get(lang=request.LANGUAGE_CODE).name for x in > > MyModel.objects.all()] > > > Hello Tomasz, > > thanks for the quick answer, however your first suggestion doesn't > work, since I don't want a queryset, I just want to display a field of > a related model for every model in the queryset.
It was just in case you don't know about it. > The second variant seems to work, even though I always get the result > for German language. But I suppose the problem is rather untested i18n > in my project than the formfield > However I'm wondering how I would transform this concept on Formsets. > I think I would somehow need to expand already the formsets __init__ > to accept the additional 'request' parameter (otherwise I get "__init__ > () got an unexpected keyword argument 'request'"), and then push it > forward to the forms __init__. I'm not sure here as I only modified Form. But I suspect that you could modify FormSet __init__ as well (although quick scan of FormSet sources has revealed some complexity there). -- Tomasz Zielinski http://pyconsultant.eu
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