I create a open botton and I change it's name properties to Openbtn and the next textbox1 to txt1. I want when I click the botton it show the open dialog box and then when I chose the file I like e.g. example.txt then I click open. then I want the text file open on the txt1 I forgot something I creat the openfiledialog I change name to OpenFd
I know some code :---- openFD.InitialDirectory = "C:\" openFD.Title = "Open a Text File" openFD.Filter = "Text Files|*.txt" openFD.ShowDialog() But It is not open the file in text box Please Help Me If You kow how to Open the file in text box tell me Thanks...
