> openFD.InitialDirectory = "C:\" > openFD.Title = "Open a Text File" > openFD.Filter = "Text Files|*.txt" > openFD.ShowDialog()
functionToOpenFile(openFD.Filename) On Jun 16, 5:41 pm, Afewerki <[email protected]> wrote: > I create a open botton and I change it's name properties to Openbtn > and the next textbox1 to txt1. I want when I click the botton it show > the open dialog box and then when I chose the file I like e.g. > example.txt then I click open. then I want the text file open on the > txt1 > I forgot something I creat the openfiledialog I change name to > OpenFd > > I know some code :---- > > openFD.InitialDirectory = "C:\" > openFD.Title = "Open a Text File" > openFD.Filter = "Text Files|*.txt" > openFD.ShowDialog() > > But It is not open the file in text box Please Help Me If You kow how > to Open the file in text box tell me > > Thanks...
