> openFD.InitialDirectory = "C:\"
> openFD.Title = "Open a Text File"
> openFD.Filter = "Text Files|*.txt"
> openFD.ShowDialog()

functionToOpenFile(openFD.Filename)

On Jun 16, 5:41 pm, Afewerki <[email protected]> wrote:
> I create a open botton and I change it's name properties to Openbtn
> and the next textbox1 to txt1. I want when I click the botton it show
> the open dialog box and then when I chose the file I like e.g.
> example.txt then I click open. then I want the text file open on the
> txt1
>    I forgot something I creat the openfiledialog I change name to
> OpenFd
>
> I know some code :----
>
> openFD.InitialDirectory = "C:\"
> openFD.Title = "Open a Text File"
> openFD.Filter = "Text Files|*.txt"
> openFD.ShowDialog()
>
> But It is not open the file in text box Please Help Me If You kow how
> to Open the file in text box tell me
>
> Thanks...

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