The usual interpretation of a p is of "results this extreme or more 
extreme".

Teresa from Oregon wrote:

>I was doing a little mental calisthenics today and got myself confused
>about how this test is calculated. My (perhaps naive) understanding is
>that all potential sets of results from, say, a 2x2 table are
>calculated and then the exact probability of the actual observed
>result occurring simply by chance is determined. This is why there is
>no associated test statistic, just p.
>
>My question is: If the test is distributionless, wouldn't the
>probability of all unique results be equal? Or...put another way...Is
>Fisher's exact one of those sneaky nonparametrics that really does
>rely upon an underlying distribution?
>
>Thanks.
>  
>

.
.
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