<< Folks, I have one question. Please let me know if any of you know the answer to my question.
I have a normal distribution with mean = 50 and standard deviation = 5 I want to divide this distribution into two separate normal distributions each with mean = 25 so that when I add them I will get my original distribution. Do any one know how to find the two separate distributions? Is the answer distribution 1 : N(25,3) and distribution 2: N(25,4) correct ? >> If you have two independent normal random set N(25,3) and N(25,4) and add them together piecevise, you will get N(50, 5). In general for two independent set the mean is the sum of the components and also the variances are the sum of the variances of the components. If you reverse it and from a normal random set N(50,5) substract an independent N(25,3) normal random set piecevise, then you will get N(25, 5.831) being the new std = sqrt(std1**2 + std2**2) http://localhost/cgi-bin/igperl/igp.pl?dir=test&name=addeddistr Now the insteresting point: If you have a normal random set N(50,5) and make two distributions on that manner, that divide each number on the ration of the expected new means ($a = $orig * $mean1 / $meanorig and $b = $orig - $a) then the resulted standard deviation also will be divided by the ration of the expected new means, on that manner that the sum of the two standard deviations will be the original (if the given new mean is larger than the orginal, then that std will be larger also), so N(50,5) divided onto two equal half each element will result N(50,2.5), N(50,2.5) sets http://localhost/cgi-bin/igperl/igp.pl?dir=test&name=dividedistr . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
