well suppose we have a communication channel and an sequence of packets cross it. One records at the end of the channel whether one received the packet or not as a 1010.... trace which is the population.
(each packet has a sequence number, packets cannot get reordered, so if 4 comes after 3, it means 2 is lost). A receives a sample of size n1 corresponding to a certain set of packets. B receives a sample of size n2 corresponding to *another* set of packets. Assuming that when the packets are sent the characteristics of the channel remain Exactly the same, the sample of A is independent of sample of B ? Now, samples of A and B are from a bernoulli population. Can one use a t-test to compare the difference of means of samples A and B ? (which is used to compare the difference of means of samples from a normal population) vijay ------------------------------------------- On Thu, 29 Apr 2004, Richard Ulrich wrote: > On Thu, 29 Apr 2004 21:15:26 +0200, Vijay Arya <[EMAIL PROTECTED]> > wrote: > > > > > I guess tossing the same coin may not make it dependent. One can use a > > single coin and generate an infinite trace of heads and tails 101001.... > > which becomes the population. > > > > Provided that A and B donot choose the same 0 or same 1 in their > > samples, the samples of A and B will remain independent. > > When I toss a quarter multiple times and catch it in the air, > the consecutive outcomes are not independent, or I never > would have hit 16 heads in a row. > > Now, if it bounces on a hard surface .... > > -- > Rich Ulrich, [EMAIL PROTECTED] > http://www.pitt.edu/~wpilib/index.html > . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
