The relationship of bandwidth and speed is that for given rise/fall
times, increasing speed will reach a point when the code elements blur
together.
So you need more bandwidth for super high-speed CW because you need to
shorten the rise and fall times. But the occupied bandwidth doesn't
change as you vary the speed.
The K3's keying waveshape and rise/fall times (the shape is important,
not just the time) are good for far faster CW than I can send!
73,
Vic, 4X6GP/K2VCO
Rehovot, Israel
http://www.qsl.net/k2vco/
On 29 Mar 2016 22:36, Jim Brown wrote:
On Tue,3/29/2016 11:28 AM, Lynn W. Taylor, WB6UUT wrote:
On 3/29/2016 10:38 AM, Jim Brown wrote:
WRONG! CW speed has NOTHING to do with bandwidth, which is determined
by RISE and FALL times of the keying waveform and distortion in the
RF stages.
So, I can occupy zero bandwidth at 10,000 wpm CW and my occupied
bandwidth will be the same as 5 wpm as long as the keying waveform is
right?
No, because even the best rise/fall waveform has SOME harmonic content,
and CW speeds of 10,000 WPM have no practical meaning. But you CAN
occupy extremely narrow (a few Hz) bandwidth with a steady carrier,
because there's nothing to excite IMD. Bandwidth would be greater than
that only to the extent that the carrier is modulated by power supply
noise or phase noise. And, of course, any distortion in the RF chain
will produce harmonics.
73, Jim K9YC
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