That's the good engineering practice to protect the output stage from
shorts. In that situation, 8 ohms will get more power than 4 ohms. It's
the classic "maximum power transfer theorem," where, when the LOAD is
variable, you get max power when the load Z is equal to the source Z. So
it comes down to which speaker is more efficient.
73, Jim K9YC
On Tue,2/7/2017 6:52 PM, Ron D'Eau Claire wrote:
To answer your question, there are 10 ohm resistors in the phones line - one in
each channel. So you are losing more than half the audio power in the
resistors. (On the plus side, you'll still have an audio output working even if
you accidentally short the audio to ground!)
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