Oops I meant to say:

"Ringing is a function of the bandwidth and only SLIGHTLY affected by the
type of filter."

-----Original Message-----
From: Ron D'Eau Claire [mailto:[EMAIL PROTECTED] 
Sent: Friday, November 30, 2007 8:52 PM
To: 'elecraft@mailman.qth.net'
Subject: RE: [Elecraft] K3 filters


Any filter will produce "ringing" when the bandwidth is too small. 

Ringing is a function of the bandwidth and only affected by the type of
filter. In some filter designs it's possible for some elements of the filter
to have such a high Q they ring even though the overall filter bandpass is
not that small, but that's a aberration in the filter design. 

Ringing typically occurs when the bandwidth at either the transmitter or
receiver is restricted too much to allow the CW sidebands to pass through.

Of course, the sidebands on a CW signal are the frequencies represented by
the rise and fall of each CW element. If the bandwidth isn't sufficient to
pass them, the element is stretched out in time as the amplitude decays,
just like the amplitude of a bell decays after the bell was stuck. That's
what we call "ringing". 

Ron AC7AC

-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Alan Bloom
Sent: Friday, November 30, 2007 1:47 PM
To: Darwin, Keith
Cc: elecraft@mailman.qth.net
Subject: RE: [Elecraft] K3 filters


For the same passband ripple and bandwidth I think more poles pretty much
invariably means more ringing.

By the way, many people think that DSP-based filters don't ring. 
Actually, a digital filter's impulse response, measured at say the
half-power point, is pretty comparable to an analog (e.g. cyrstal) filter
with the same ripple and bandwidth.  However, the ringing from a digital FIR
(finite impulse response) filter eventually drops all the way to zero, while
an IIR (e.g. analog) filter theoretically rings forever.  Since human sound
perception tends to be logarithmic, the ringing _sounds_ longer with the
analog filter.

Al N1AL


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