On Nov 17, 2008, at 3:01 PM, Kok Chen wrote:
Prob( (s+n1+n2)^2 ) = Prob(s^2 + n1^2 + n2^2 + n1.n2 + s.n1 +
s.n2). If s, n1 and n2 are uncorrelated, then Prob(n1.n2) =
Prob(s.n1) = Prob(s.n2) = 0.
Whoops, that should be
Prob( (s+n1+n2)^2 ) = Prob(s^2 + n1^2 + n2^2 + 2.n1.n2 + 2.s.n1 +
2.s.n2) (I should have counted that there are 9 terms altogether on
the right hand side :-).
But the average of ( n1.n2 ) = 0 implies that the average of
( 2.n1.n2 ) is also identically zero, etc...
73
Chen, W7AY
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