Eric AC 498 A>C 498 BC 497 B>C 497 CA 3 C>A 3 CB 2 C>B 2 In an election comparing A with B and ignoring C result A 501, B 499 In an election comparing A with C and ignoring B result A 498, C 502 In an election comparing B with C and ignoring A result B 497, C 503 A beats B, C beats A , C beats B. In pairwise comparison C beats all other candidates and therefore is the winner. How is this wrong ? By 498 AC I meant 498 voters ranked A 1st and C 2nd, 497 BC 497 ranked B 1st and C 2nd, 3CA 3 ranked C 1st and A 2nd, 2CB 2 ranked C 1st and B 2nd. I put what I meant into the Condorcet calculator on your site with A as 0, B as 1 and C as 2 and option 2 (C) won under all three methods. Considering what I wrote if this is wrong I'll have no shortage of answers. David Winners: Option Did it win? 0 no 1 no 2 YES Option 0 1 2 0 0 501 498 1 499 0 497 2 502 503 0 |
