Markus, --- Markus Schulze <[EMAIL PROTECTED]> a �crit�: (Tengvall description moved to the bottom)
I think you may have misunderstood Tengvall's method: > In short: The Tengvall winner is that Schwartz winner A whose > worst pairwise comparison with another candidate B (measured > by the absolute number of voters who strictly prefer candidate B > to candidate A) is minimal. I believe it is rather: that Schwartz winner A whose worst pairwise comparison with another candidate B (measured by the absolute number of voters who strictly prefer candidate *A* to candidate *B*, plus the number of voters ranking them equal) is *maximal*. If I've understood Tengvall correctly, these ballots: 49 A 24 B 27 C>B produce a B-C tie. Scores: A:B 49:51, A:C 73:51, B:C 73:76 Seems something is lacking here. Tengvall should be alerted. Kevin Venzke [EMAIL PROTECTED] > > 1. Count votes in all pairwise comparisons, according to this: > > Count a vote to X from every ballot where X is given better or > > equal preference than Y, and to Y from every ballot where Y is > > given better or equal preference than X. X beats Y if the former > > score is bigger than the latter, and vice-versa. > > > > 2. The vote minimum of each X is the smallest score of X in any > > of X:s comparisons. > > > > 3. There is a beatpath from X to Y if X beats Y (in pairwise > > comparison between these two) or X beats some Z that beats Y. > > > > 4. Eliminate every candidate X such that there is a beatpath > > from some Y to X but not vice-versa. > > > > 5. Check the vote minimum of each non-eliminated. The winner > > is the one with the biggest vote minimum. (A tie is possible.) ___________________________________________________________ Do You Yahoo!? -- Une adresse @yahoo.fr gratuite et en fran�ais ! Yahoo! Mail : http://fr.mail.yahoo.com ---- Election-methods mailing list - see http://electorama.com/em for list info
