Matt said (referring to Eric's count program):
I tried 4:A>C>B 10:A>B>C 6:B>A>C 8:B>C>A 6:C>B>A 9:C>A>B
which translates to 24:B>C 23:C>A 23:A>B
My PERL script computes this as a win for B. You compute it as tie for A & B.
I reply:
Based on the numbers that Matt gave, it's a tie between A & B. In fact, a 3-candidate example doesn't even require a computer to determine the winner.
Perhaps Matt should hire someone who is able to code perl.
With 3 candidates, MAM (aka RP), SSD, CSSD, & PC all give the same outcome: The winner is the candidate whose defeat is the least.
Mike Ossipoff
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