Wasn't going to weigh in on this one, but there are a few inaccuracies here
which require correction.  No criticism implied, I can't remember where I
placed my keys five minutes ago; I will not criticize a lapse of memory over
40 years.

Energy or power density from a point source spreading out into a sphere
drops as the square of the distance traveled, since the surface area of the
sphere is 4*pi*r^2, and energy is conserved.  Note this has nothing to do
with light per se.  It just is.

Electromagnetic energy can travel in a complete vacuum, devoid of any matter
whatsoever.  The electric and magnetic fields associated with a traveling
electromagnetic wave are displacements in the very fabric of space itself.
This was demonstrated by Michelson-Morley either very late in the nineteenth
or very early in the twentieth century.

Ken Javor

----------
>From: geor...@lexmark.com
>To: george_t...@dell.com
>Cc: brian_ku...@leco.com, emc-p...@majordomo.ieee.org
>Subject: RE: How does RF travel through outer space?
>Date: Thu, Nov 30, 2000, 4:10 PM
>

>
> Geez, this question makes me feel like I'm on "Who want to be a millionaire"!
> Brain should have provided multiple choices for his two questions.
>
> George, good anaolgy re the pumpkin.  Here is some other stuff I remember
> from my hated electric field classes some 40 years ago.  If the radiator is a
> point
> source in space, and the energy is equally distributed in a spherical pattern,
> the
> energy at any point in space drops off as the cube of the distance from the
> source.
> If the radiator is an infinite line, the energy drops off as the square of the
> distance
> from the source.   If the source is an infinite plane, the energy remains the
> same
> regardless of the distance from the plane.  Are these right?
>
> Now to the tough part about RF travelling in space.  Note that all energy we
> receive from the sun comes in some form of electromagnetic energy, ranging
> from frequncies which give us light, to infrared which gives us heat, in
> addition
> to all kinds of non-structered RF signals.
>
> Doesn't electromagnetic energy depend on the sequential exitation of electrons
> from one adjacent molecule to another to "travel" anywhere?  It is my
> understanding
> that space is not a vacuum, but merely a lower pressure than that here on
earth.
> The
> molecules may be further apart (less dense), but are still out there.  The
only
> TRUE
> vacuum I know of is what they call a "black hole" in space, which literally
> sucks all
> nearby matter into it......but this is still a theory.
>
> Brain, the RF energy, or any other part of the EM spectrum, travels through
> space
> just as in the water you mentioned, only with different molecules, and spacing
> of
> same.
>
> These are my FINAL answers.  Did I win anything, or must I go home a loser?
>
> George
>
>
>
>
> george_tang%dell....@interlock.lexmark.com on 11/30/2000 03:56:59 PM
>
> Please respond to george_tang%dell....@interlock.lexmark.com
>
> To:   brian_kunde%leco....@interlock.lexmark.com,
>       emc-pstc%majordomo.ieee....@interlock.lexmark.com
> cc:    (bcc: George Alspaugh/Lex/Lexmark)
> Subject:  RE: How does RF travel through outer space?
>
>
>
>
> We all just carved pumpkins not too long ago.  We can use pumpkins to
> explain one of these questions.  If you put a 5 watt light bulb at the
> center of your carved pumpkin, then each square inch of the internal pumpkin
> surface gets the amount of light energy given by the expression:
>
> 5W / (internal surface area of pumpkin) = light energy per square inch
>
> Now you move your light bulb to a bigger pumpkin and do the same
> calculation.  You find that each square inch of your bigger pumpkin gets
> less light energy due to a bigger surface area.  This is why RF signals drop
> off at the rate of 1/distance squared, since the pumpkin surface area is
> proportional to the square of the radius.  Light is simply a higher
> frequency emission than RF, but the same concept applies.
>
> As far as "How RF travel through vacuum," you can think of it this way:  RF
> is composed of electric field and magnetic field.  Electric field is simply
> the attraction force between the positive charges and the negative charges.
> And magnetic field is the interaction between 2 current loops.  It is not
> hard to imagine that refrigerator magnets will work in vacuum or protons and
> electrons will attract in outer space.  RF is simply the electric and
> magnetic fields changing polarity at a very rapid rate.
>
> George
>
>
>
> -----Original Message-----
> From: brian_kunde [mailto:brian_ku...@leco.com]
> Sent: Thursday, November 30, 2000 12:51 PM
> To: emc-pstc
> Subject: How does RF travel through outer space?
>
>
>
>
>
> Hello,
>
> I'm sorry if this is too simple of question... "How does RF travel through
> outer
> space?".
>
> I will be teaching a class in which this question will come up. I want to be
> prepared with all the basic science behind this principal. I need an
> explaination that is simple and easy to understand.
>
> People seem to have no problem understanding how waves can travel through
> mass
> such as a body of water but can not understand how it can travel where there
> is
> no mass. I also understand that there is a lot of debate over how Light
> travels
> through space (photons and all).
>
> Also, I understand that RF signals degrade at a rate of 1/distance(squared).
> What force is causing this attenuation?
>
> Try to keep it simple for my audience it not all that technical.  Appreciate
> the
> help. Please forgive any improper punctuation or word misuse.
> Brian
>
>
>
>
>
>
>
>
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