George,

I am impressed by your attitude to pursue the correctness, and glad to discuss 
with you further on “How does a decoupling capacitor support an IC?”

Here is my two cents worth. The decap supplies necessary charge to the IC 
during Tr through a transmission line. As you mentioned before: “The current is 
an impulse function, although the voltage waveform is a step function.” This 
impulse function, actually a bell-like function on Tr, happens every time 
period T when the IC gate switches from low to high. The corresponding 
frequency spectrum contains lots of frequencies. There must be some frequencies 
making the transmission line a 1/4, 3/4, ... wavelength. It is hard for me to 
be convinced that currents of those frequencies cannot flow from the decap to 
the IC. ... Pleas correct me if misunderstood. Thanks.

Regards,
Barry Ma
b...@anritsu.com

--------
On Mon, 22 May 2000, george_t...@dell.com wrote:

> 
> Barry, 
> 
> I need to make a correction.  I was rushing to lunch on Thursday, so I did
> not read over what I wrote.  Here is the correction for the 2nd comment
> below: 
> 
> At 1/4 wavelength, the charges are 180 degrees out of phase, so they are
> working against the IC current draw.  1/8 wavelength (90 degrees out of
> phase) is what I consider to be acceptable.  
> 
> Regards, 
> 
> George Tang
> george_t...@dell.com


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