If the power supply voltage is "stiff", then all you need measure is the
average current. The average current times the voltage will give you the
correct average power.

If the supply voltage is not stiff, then the process is more complex. You
will need to measure the voltage and the current, multiply them
point-by-point, and then average.

Measuring RMS current in this case is WRONG. RMS measurements are used when
voltage and current vary in direct proportion to each others (as in a
resistor). That is, when the current goes up across the load, the voltage
goes up in the same proportion. In a power supply, the output voltage will
most likely DECREASE a bit as the load current INCREASES. While you can
still make an RMS current measurement even in this case, it will NOT tell
you the average power consumption.

Don Borowski
Schweitzer Engineering Labs
Pullman, WA





<rbus...@es.com>@majordomo.ieee.org on 02/17/2003 12:19:27 PM

Please respond to <rbus...@es.com>

Sent by:    owner-emc-p...@majordomo.ieee.org


To:    <emc-p...@majordomo.ieee.org>
cc:
Subject:    Measuring  Power Supply Output Current



I have been asked by my TUV office to measure the actual output current
for each of the 5-7 voltages on my PC power supplies. The purpose of
this is to baseline the maximum output current in terms of maximum
power, not instantaneous current, for each of the various motherboards
we use.

On the surface it seemed like a simple exercise of putting a DC current
meter in series with each of the outputs. Given that the current demand
for each of these outputs is dynamic, corresponding with the processing
activity, does it make sense to measure this output current with a True
RMS meter?

If this is the case, I would assume that the True RMS meter takes the
measurement based on some type of a time weighted average or sample
time. Do any of you have a feel for how this is calculated?

How do manufacturers of these PC supplies address the maximum output
current ratings for each voltage. Does this rating take into account
PEAK demands for current (or over current)?

Thanks

Rick Busche
Evans & Sutherland
rbus...@es.com



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