It is true that the unit dB Ohm has to be interpreted in context.  However
that does not change its utility.  Current probe transfer impedance and
shielding transfer impedance both have units of dB Ohm.  What would be a
better substitute?

> From: John Woodgate <j...@jmwa.demon.co.uk>
> Reply-To: John Woodgate <j...@jmwa.demon.co.uk>
> Date: Thu, 18 Dec 2003 22:58:02 +0000
> To: emc-p...@majordomo.ieee.org
> Subject: Re: CISPR 25 Conducted Emissions (Current Method)
> 
> 
> I read in !emc-pstc that scott....@jci.com wrote (in
> <of227b3f0b.4367e65e-on85256e00.0056b9fa-85256e00.0056d...@jci.com>)
> about 'CISPR 25 Conducted Emissions (Current Method)' on Thu, 18 Dec
> 2003:
>> Please read the attached document that he assembled for the details.
> 
> Not relevant to the question, but I'm very disappointed to see
> 'dB(ohm)'. The point is that this concept is mathematically nonsense.
> 
> Consider V = IR
> 
> 20logV = 20log(IR) = 20log I + 20log R
> 
> Now consider
> 
> P = I^2R
> 
> 10logP = 10log(I^2) + 10logR
> 
> So is the 'dB(ohm)' 20logR or 10logR?
> 
> The UK national EMC committee has pointed this out to CISPR committees
> on several occasions, but the mistake keeps being made.
> -- 
> Regards, John Woodgate, OOO - Own Opinions Only. http://www.jmwa.demon.co.uk
> Interested in professional sound reinforcement and distribution? Then go to
> http://www.isce.org.uk
> PLEASE do NOT copy news posts to me by E-MAIL!
> 
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