Doug, The standard must assume the RF circuits are even more energy-limited 
than secondary circuits is my best guess.  If so, it doesn't say that anywhere 
I could find.  It takes voltage, but also energy to create an ionizing path.   
Regards,  Brian Gregory
720-450-4933

---------- Original Message ----------
From: Doug Powell <doug...@gmail.com>
To: EMC-PSTC@LISTSERV.IEEE.ORG
Subject: [PSES] IEC 61010-1 Table K.17
Date: Fri, 7 Aug 2015 16:47:28 -0600


All,
 
 I am evaluating spacings for an RF product that operates at 13.56 MHz and can 
produce maximum voltages of 5,000 Vrms (7,070 Vpk).  If I do an interpolation 
of using Table 6 (Mains 230 V, OV Cat II, indexing on 5,000 Vrms), I get a 
minimum clearance requirement of 14.9 mm.  When I do the same calculation on 
Table K.17 (column 3, indexing on 7,070 Vpk), I get 12.7 mm.  
 
 Now I understand the effects of high frequency voltage stress causing air 
molecules to become more energetic and therefore more likely to break down at 
lower voltages.  So why in this case does IEC 61010-1 Table K.17 result in 
lower clearance values than Table 6?  Somehow, this just seems wrong.
 
 Please note that in the case of high frequencies paragraph K.3.1 indicates I 
am to skip over section K.3.2 with the D1 + F × (D2 &ndash; D1) calculations.
 
 Thanks a bunch!
 
 Doug
 
 Douglas E Powell
 doug...@gmail.com
 http://www.linkedin.com/in/dougp01
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