Why is it important that the signals be close to 90 degrees out of
phase?  Here's why: imagine they're some smaller amount (e.g., 45
degrees).  That means that there's a smaller time for at least one of
the 4 states of the quadrature progression at any given speed.  In the
45 degree case, it makes the maximum accurate count rate only half of
what it could optimally be for a perfect 90 degree phase differences.

Jeff

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