Igor Chudov wrote: > Been reading the datasheet for the resolver: 11BRW-300-F10-10.pdf > > http://igor.chudov.com/manuals/Harowe-Resolvers/11BRW-300-F10-10.pdf > > It calls for input voltage of 12 volts. I think that I give it much less > than that, 4.7 volts or so. > The resolver is a transformer, which varies the coupling with rotation. The AD2S1200 chip MUST have approximately 3.6 V P-P when the resolver is turned to the maximum coupling on that stator coil. So, forget the rated input voltage on the resolver. What you MUST do is set the excitation level, with the jumpers, to satisfy the input signal requirement.
If the resolver has a 1:1 winding (12 V in, 12 V out) then 4.7 V input would be about right. > Still trying to make sense of it, but I think I need more voltage on input. > Set the OUTPUT to 3.6 V P-P at the peak angle of the resolver and see how it works. That is the procedure given by Analog Devices for their chip. Jon ------------------------------------------------------------------------------ Special Offer-- Download ArcSight Logger for FREE (a $49 USD value)! Finally, a world-class log management solution at an even better price-free! Download using promo code Free_Logger_4_Dev2Dev. Offer expires February 28th, so secure your free ArcSight Logger TODAY! http://p.sf.net/sfu/arcsight-sfd2d _______________________________________________ Emc-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/emc-users
