Been reading the datasheet for the resolver: 11BRW-300-F10-10.pdf
http://igor.chudov.com/manuals/Harowe-Resolvers/11BRW-300-F10-10.pdf
It calls for input voltage of 12 volts. I think that I give it much less
than that, 4.7 volts or so.
This could explain why things are bad in every quadrant, when sine and
cosine together are only 50% of 4.7/sqrt( 2 ).
Still trying to make sense of it, but I think I need more voltage on input.
i
On Sat, Jan 29, 2011 at 11:04 PM, Igor Chudov <ichu...@gmail.com> wrote:
> Another finding, somewhat surprising.
>
> These "speedups/slowdowns" occur four times in a complete circles. This
> means that as the shaft turns one full turn, it would slow down four times
> and speed up four times. So, something happens in every quarter of a full
> turn.
>
> i
>
11BRW-300-F10-10.pdf
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