----- Original Message ----- 
From: "gene heskett" <ghesk...@wdtv.com>
To: <emc-users@lists.sourceforge.net>
Sent: Thursday, March 10, 2011 9:30 AM
Subject: Re: [Emc-users] Single Phase Lathe spindle motor question


> On Thursday, March 10, 2011 10:25:58 AM RogerN did opine:
>
>> >----- Original Message -----
>> >From: "andy pugh" <bodge...@gmail.com>
>> >To: "Enhanced Machine Controller (EMC)"
>> ><emc-users@lists.sourceforge.net> Sent: Thursday, March 10, 2011 4:59
>> >AM
>> >Subject: Re: [Emc-users] Single Phase Lathe spindle motor question
>> >
>> >On 10 March 2011 01:24, gene heskett <ghesk...@wdtv.com> wrote:
>> >> But that was a 20HP motor, running on 235V 3 phase, and drew 39
>> >> amps/phase
>> >> at rated power output. So a 100 HP motor would have needed only 195
>> >> amps, not 330/phase.
>> >
>> >195A per phase on 3-phase input. Wouldn't it be 50% more on
>> >single-phase input? (Or would it be 3x as much?)
>>
>> 3-phase amps X 1.732 (SqRt of 3) = 3 phase amps (not dealing with
>> changes in power factor)
>>
>> Roger Neal
>
> Wouldn't that be:
> 3-phase amps X 1.732 (SqRt of 3) = single phase amps?
>
> But then the supply would also be scaled, from the 240 range to 252 due to
> the lack of the vector additions the 120 degree phase angle causes in the 
> 3
> phase scenario.  I'm confused enough without that. ;-)
>
> -- 
> Cheers, Gene

Oops, yeah, I meant single phase.

I believe the formula for electrical horsepower would be something like 
volts X amps (X 1.732 for 3 phase)X power factor X efficiency / 746.

Roger Neal


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