Are you sure it is cancelling cutter comp or is it changing cutter comp to the other side of the programmed path?
On Jul 2, 2017 4:50 PM, <[email protected]> wrote: Yes, I do see different results, the line becomes horizontal rather than angled. But my question is, why when cutter compensation IS on, are the moves treated differently. By the way, even if we change the first G0 to a G1, we still get the angled line. So, it isn’t G0 vs G1, it is simply that the first move is lower than it should be (by the tool diameter in the tool table) and the second move in Z causes X to rise to the compensated value. How/why? -Tom > On Jul 2, 2017, at 5:29 PM, Stuart Stevenson <[email protected]> wrote: > > You SHOULD see different results. > > On Jul 2, 2017 3:46 PM, <[email protected]> wrote: > >> I don’t disagree but am failing to see the connection to my question…? >> -Tom >> >>> On Jul 2, 2017, at 4:16 PM, Stuart Stevenson <[email protected]> wrote: >>> >>> It has always been my experience G40 cancels cutter compensation. >>> >>> On Jul 2, 2017 2:44 PM, <[email protected]> wrote: >>> >>> Why would G0 to a given location in one axis (X) differ such that a G1 >>> movement in another axis (Z) causes the first axis to move? Let me >>> explain... >>> >>> Attached is a screenshot of the back plot from Axis: >>> http://bgp.nu/~tom/pub/G0G1.png >>> >>> The highlighted line is "G0 X#<CurrentDiameter>" >>> >>> However, if you look at the back plot that IS NOT the CurrentDiameter >> value >>> where it landed. It MIGHT be "CurrentDiameter - Cutter Compensation”. >>> >>> But then 2 lines down I move "G1 Z#<Z-Start>" and the line rises up to >>> CurrentDiameter. That is, the move “G1 Z#<Z-Start>” is also causing a >>> move in X to CurrentDiameter (when it should already be there - but >> isn’t). >>> Why is this? Why is the G0 move different from the G1 move? Or phrased >>> another way, why is that first line at an angle rather than horizontal? >>> >>> According to the G-Code reference it appears both G1 and G0 are both >>> affected by cutter compensation so they should be the same shouldn’t >> they? >>> >>> -Tom >>> >>> >>> ------------------------------------------------------------ >>> ------------------ >>> Check out the vibrant tech community on one of the world's most >>> engaging tech sites, Slashdot.org! http://sdm.link/slashdot >>> _______________________________________________ >>> Emc-users mailing list >>> [email protected] >>> https://lists.sourceforge.net/lists/listinfo/emc-users >>> ------------------------------------------------------------ >> ------------------ >>> Check out the vibrant tech community on one of the world's most >>> engaging tech sites, Slashdot.org! http://sdm.link/slashdot >>> _______________________________________________ >>> Emc-users mailing list >>> [email protected] >>> https://lists.sourceforge.net/lists/listinfo/emc-users >> >> >> ------------------------------------------------------------ >> ------------------ >> Check out the vibrant tech community on one of the world's most >> engaging tech sites, Slashdot.org! http://sdm.link/slashdot >> _______________________________________________ >> Emc-users mailing list >> [email protected] >> https://lists.sourceforge.net/lists/listinfo/emc-users >> > ------------------------------------------------------------ ------------------ > Check out the vibrant tech community on one of the world's most > engaging tech sites, Slashdot.org! http://sdm.link/slashdot > _______________________________________________ > Emc-users mailing list > [email protected] > https://lists.sourceforge.net/lists/listinfo/emc-users ------------------------------------------------------------ ------------------ Check out the vibrant tech community on one of the world's most engaging tech sites, Slashdot.org! http://sdm.link/slashdot _______________________________________________ Emc-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/emc-users ------------------------------------------------------------------------------ Check out the vibrant tech community on one of the world's most engaging tech sites, Slashdot.org! http://sdm.link/slashdot _______________________________________________ Emc-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/emc-users
