On Tue, Apr 19, 2011 at 11:52 AM, Brendan Eich <bren...@mozilla.com> wrote:
> So ASI does *not* change program behavior from non-error behavior A to > non-error behavior B. It instead suppresses early SyntaxError with > successful evaluation, in a deterministic way. Is that true even in the "return \n expression" case? It certainly seems to be not an error before or after ASI, yet the result is quite different. -- John A. Tamplin Software Engineer (GWT), Google
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