On 01.11.2011 23:46, Allen Wirfs-Brock wrote:
On Nov 1, 2011, at 12:27 PM, Jeremy Ashkenas wrote:
On Tue, Nov 1, 2011 at 3:21 PM, Axel Rauschmayer <a...@rauschma.de
<mailto:a...@rauschma.de>> wrote:
Another problem: What if an instance method makes a super-call?
A slightly less elegant (and performant) variant of your solution
that works in both of the above cases is:
- Keep track (per object and method) of the object where the
previous super-call (e.g. super.foo()) ended up.
- Start your search either there or at |this|: look for the
*second* occurrence of property "foo". [optional: optimize
non-|this| case]
Nope -- I think that design isn't the correct semantics. super()
exists to delegate back to parent implementations of *the current
method*. When calling a different instance method the calls should
always start back out at the bottom of the inheritance hierarchy --
not at whatever level you happened to be on at the time.
Who says? See
https://github.com/allenwb/ESnext-experiments/blob/master/ST80collections-exp1.js#L419
Note that this is a direct transliteration of code from one of the
first and longest lived object-oriented class libraries (see comments
at the head of the file). So super calls to "other methods" have a
long history. It is a relatively rare technique, but sometimes it is
essential. In this particular case, a super call to the same method
would produce a loop. In this case choice of doing this.do and
super.do needed to be made by the original programmer based upon their
decomposition of methods.
Yes, I agree that ability to define own super method name is useful (and
some languages require it, even for constructors, e.g. Python).
However, another question I have. More often it's needed only to call
the parent method exactly with the same name. Can we may it's optional?
I mean, if syntactic for is super(...), then we take the name from the
caller function's name. Else, in case of super.foo(...) the name is
specified explicitly.
Dmitry.
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